You are given a pointer to the root of a binary tree. You need to print the level order traversal of this tree. In level order traversal, we visit the nodes level by level from left to right. You only have to complete the function. For example:

     1
      \
       2
        \
         5
        /  \
       3    6
        \
         4

For the above tree, the level order traversal is 1 -> 2 -> 5 -> 3 -> 6 -> 4.

Input Format

You are given a function,

void levelOrder(node * root) {

}

Constraints

1Nodes in the tree500

Output Format

Print the values in a single line separated by a space.

Sample Input

     1
      \
       2
        \
         5
        /  \
       3    6
        \
         4

Sample Output

1 2 5 3 6 4

Explanation

We need to print the nodes level by level. We process each level from left to right.
Level Order Traversal: 1 -> 2 -> 5 -> 3 -> 6 -> 4.

Code:

"""
Node is defined as
self.left (the left child of the node)
self.right (the right child of the node)
self.data (the value of the node)
"""
import Queue
def levelOrder(root):
   #Write code Here
    node = None
    q = Queue.Queue()
    q.put(root)
    result = []
    while not q.empty():
        node = q.get()
        result.append(node.data)
        if node.left is not None:
            q.put(node.left)

        if node.right is not None:
            q.put(node.right)

    for i in result:
        print i,